20y^2+7y-3=

Solution for 20y^2+7y-3= equation:

Simplifying
20y2 + 7y + -3 = 0

Reorder the terms:
-3 + 7y + 20y2 = 0

Solving
-3 + 7y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-3 + -5y)(1 + -4y) = 0

Subproblem 1
Set the factor '(-3 + -5y)' equal to zero and attempt to solve:

Simplifying
-3 + -5y = 0

Solving
-3 + -5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -5y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -5y = 0 + 3
-5y = 0 + 3

Combine like terms: 0 + 3 = 3
-5y = 3

Divide each side by '-5'.
y = -0.6

Simplifying
y = -0.6
Subproblem 2
Set the factor '(1 + -4y)' equal to zero and attempt to solve:

Simplifying
1 + -4y = 0

Solving
1 + -4y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4y = 0 + -1
-4y = 0 + -1

Combine like terms: 0 + -1 = -1
-4y = -1

Divide each side by '-4'.
y = 0.25

Simplifying
y = 0.25
Solution
y = {-0.6, 0.25}